函数f(x)是定义在R上的偶函数，且f(1+x)=f(1-x),当-1≤x≤0时,f(x)=-(1/2)x,则f(8.6)=＿＿＿
热心网友
解：∵f(x)是定义在R上的偶函数∴x = 0是y = f(x)对称轴；又∵f(1+x)= f(1－x) ∴x = 1也是y = f (x) 对称轴。故y = f(x)是以2为周期的周期函数，∴f (8.6 ) = f (8+0.6 ) = f (0.6 ) = f (－0.6 ) = 0.3
热心网友
because f(1+x)=f(1-x) so f(x)=f(2-x) because偶函数so f(x)=f(x-2) so f(8.6)=f(8.6-2)=(6.6-2)=......=f(0.6)f(0.6)=f(-0.6)=-(1/2)*(-0.6)=0.3明白了吗?不要辜负了我的一片心意呦!!!!