0<x-2/x+2<1/2 的解集.x(x-5)^2>3(x-5)^2的解.x^2(x-1)(x-4)(x+3)^3 (x^2-x+1)>0的解集.
热心网友
1)0=(x-2)/(x+20 & (x-2)/(x+2)-1/2(x+2)(x-2)0 & [2(x-2)-(x+2)]/[2(x+2)]---x2; & (x-6)/(x+2)x2 & -223(x-5)^2---x(x-5)^2-3(x-5)^20---(x-3)(x-5)^20(x-5)^2=0---x3 & x5.3)x^2*(x-1)(x-4)(x-3)^3*(x^2-x+1)0x^2=0, x^2-x+1=(x-1/2)^2+3/40恒成立。并且(x-3)^3与x-3的符号完全相同。所以原不等式与x0 & (x-4)(x-1)(x+3)0同解.使用零点区分法可以得出：-34
热心网友
04/(x+2)∈(1/2,1)----(x+2)∈(4,8)----x∈(2,6)x(x-5)^3(x-5)^的解.----(x-3)(x-5)^0----x3且x≠5x^(x-1)(x-4)(x+3)^3(x^-x+1)0的解集. ----(x+3)x^(x-1)(x-4)[(x-1/2)^+3/4]0----x4或0