设M=x(x-y-2)+9,N=(y+2)(3-y),则有( )A.M>N B.M≥NC.M<N D.M≤N

热心网友

判断两数的大小,一般用作差法M-N=x^2-xy-2x+9-3y-6+y^2+2y=[(x-y)^2+(x-2)^2+(y-2)^2+1]/2为了计算方便,在此设了个分母2此时分子大于零即MN