以知等式5x^2-6xy+2y^2-4x+2y+1=0则（2x+y)=？（一定要写步骤呀！）帮忙啦！
热心网友
0=5x^2-6xy+2y^2-4x+2y+1==(x^2-2xy+y^2)+(4x^2-4xy+y^2)-2(2x-y)+1==(x-y)^2+(2x-y)^2-2(2x-y)+1==(x-y)^2+(2x-y-1)^2==x-y=0,2x-y-1=0==x=y=12x+y=3.
以知等式5x^2-6xy+2y^2-4x+2y+1=0则（2x+y)=？（一定要写步骤呀！）帮忙啦！
0=5x^2-6xy+2y^2-4x+2y+1==(x^2-2xy+y^2)+(4x^2-4xy+y^2)-2(2x-y)+1==(x-y)^2+(2x-y)^2-2(2x-y)+1==(x-y)^2+(2x-y-1)^2==x-y=0,2x-y-1=0==x=y=12x+y=3.