热心网友
X0,y02X+3Y=6得2X*3Y≤[(2X+3Y)/2]^=3^2=9xy≤3/2log2^x+log2^y=log2^(xy)≤log2^(3/2)=log2^3-1log2^x+log2^y的最大值是log2^3-1
热心网友
6=2x+3y≥2√(2x*3y)=2√6√(xy),得√(xy)≤√6/2,得xy≤3/2.√[Log2(x)Log2(y)≤{Log2(x)+Log2(y)]/2=Log2(xy)/2=Log2(3/2)/2=[Log2(3)-1]/2两边平方得Log2(x)Log2(y)≤[Log2(3)-1]平方/4(即最大值)