若(√2/2)^x=4√2,求(x-1)/【x^(2/3)+x^(1/3)+1】.谢谢了!!
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若(√2/2)^x=4√2,求(x-1)/【x^(2/3)+x^(1/3)+1】.因为x-1=[x^(1/3)-1]*[x^(2/3)+x^(1/3)+1] （立方差公式）所以原式＝x^(1/3)-1 因为 (√2/2)^x=4√2 ,所以1/(√2)^x = (√2)^5所以 x=-5 所以原式＝ -5^(1/3) -1
若(√2/2)^x=4√2,求(x-1)/【x^(2/3)+x^(1/3)+1】.谢谢了!!
若(√2/2)^x=4√2,求(x-1)/【x^(2/3)+x^(1/3)+1】.因为x-1=[x^(1/3)-1]*[x^(2/3)+x^(1/3)+1] （立方差公式）所以原式＝x^(1/3)-1 因为 (√2/2)^x=4√2 ,所以1/(√2)^x = (√2)^5所以 x=-5 所以原式＝ -5^(1/3) -1