热心网友

Lim{n→∞}{n-1/[e^(1/n)-1]}=Lim{n→∞}{n-1/[1/n+1/2n^2]}==Lim{n→∞}{n-n/[1+1/2n]}=Lim{n→∞}{n-n[1-1/2n]}=1/2.