定义在[-1,1]上的??函数f(x),不等式f(2x+1)<f(3x+2)的解集( )A.{x/x>-1} B.{x/-1<=x<=0} C.{x/-1<=x<=-1/3} D.{x/-1<x<=-1/3}

热心网友

选C根据不等式 -1<=2x+1<=1 -1<=3x+2<=1 2x+1<3x+2可得答案