已知a>2,求证loga(a-1)*loga(a+1)<1
热心网友
已知a2,求证loga(a-1)*loga(a+1)loga(ａ^-1)=loga(ａ-1)(ａ+1)=loga(ａ-1)+loga(ａ+1)2√[loga(ａ-1)loga(ａ+1)]∴22√[loga(ａ-1)loga(ａ+1)]∴loga(a-1)*loga(a+1)<1
热心网友
给个片片：
热心网友
证:√[Loga(a-1)*Loga(a+1)<[Loga(a-1)+Loga(a+1)]/2=Loga(a-1)(a+1)/2=Loga(a^2-1)/2