请分析并解答，谢谢~~
热心网友
根据题意有：U1=U2 == I1R1=I2R2 ==I2=I1R1/R2=2R1/2=R1I1+I2=I3, U=U1+U3=U2+U3 ==U=I1R1+P3/(I1+I2)=2R1+15/(2+R1)=9所以 ==(R1-3)(2R1+1)=0 ==R1=3Ω(舍负)所以 ==U3=U-U1=9-6=3V ==R3=U3^2/P3=9/15=3/5Ω
热心网友
R3=3/5欧姆R1=5/2欧姆
请分析并解答，谢谢~~
根据题意有：U1=U2 == I1R1=I2R2 ==I2=I1R1/R2=2R1/2=R1I1+I2=I3, U=U1+U3=U2+U3 ==U=I1R1+P3/(I1+I2)=2R1+15/(2+R1)=9所以 ==(R1-3)(2R1+1)=0 ==R1=3Ω(舍负)所以 ==U3=U-U1=9-6=3V ==R3=U3^2/P3=9/15=3/5Ω
R3=3/5欧姆R1=5/2欧姆