解不等式:(1)|x+1|小于等于2-x (2)|x+1|>2-x(3)|2|x|-3|<|x|+1

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1.|x+1|2-x=0.....(1),x-2=2-x==若2-x2....(1);若2-x=0,有x+12-x或x+12/3 -4