一质点由静只做匀加速直线运动，加速度大小为a,经时间t后做匀减速直线运动，加速度大小为b，若再经过时间t恰能回到出发点，则a:b[] 拜托给个作题过程！
热心网友
根据加速度的定义公式a=v/tv=at=bt∴a=ba:b=1:1
热心网友
wrong!go back to the original pointshould be:(1/2)at^2=-(at*t)-(1/2)bt^23at^2=-bt^2a:b=-(1:3)here "-" means the different direction of a and b.
热心网友
(1/2)at^2=at*t-(1/2)bt^2at^2=bt^2a=ba:b=1