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求证数列{4n/(n^+1)}是递减数列证：an=4n/(n^+1)=4/[n+(1/n)]而n+(1/n)≥2√[n*(1/n)]=2，即：n=1时，n+(1/n)有最小值2即：n=1时，an有最大值4/2=2∴数列{4n/(n^+1)}是递减数列
求证数列{4n/(n^+1)}是递减数列证：an=4n/(n^+1)=4/[n+(1/n)]而n+(1/n)≥2√[n*(1/n)]=2，即：n=1时，n+(1/n)有最小值2即：n=1时，an有最大值4/2=2∴数列{4n/(n^+1)}是递减数列