奇函数f(x)满足f(x+2)=f(x),若f(x)在区间(-3,-2)上递减且f(x)>0则A.f(-2/3)<f(-1/2)B.f(-2/3)>f(-1/2)C.f(-2/3)=f(-1/2)D.f(-2/3)与f(-1/2)的大小关系要视对应规律f而定请简要写出解答过程,谢谢!
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因为f(x)=f(x+2),将x换成t-2,所以f(t-2)=f(t),即f(x-2)=f(x)所以f(-2/3)=f(-2/3-2)=f(-8/3),f(-1/2)=f(-1/2-2)=f(-5/2),而-5/2-8/3,而函数在(-3,-2)上递减,所以f(-5/2)f(-1/2)