1.X^-(m^+n^)+mn(m^-n^)2.(x+y)(x+y+2xy)+(xy+1)(xy-1)3.x^-6y^-12z^+xy-xz+17yz(既要答案，又要过程）
热心网友
1。x^2-(m^2+n^2)x+mn(n^2-m^2);2。(x+y)(x+y+2xy)+(xy+1)(xy-1);3。x^2-6y^2-12z^2+xy-xz+17yz。现解答如下:1。原式=x^2-(m^2+n^2)x-mn(m+n)(m-n)=x^2-(m^2+n^2)x+[-m(m+n)][n(m-n)]=[x-m(m+n)][x+n(m-n)]=(x-m^2-mn)(x+mn-n^2);2。原式=(x+y)^2+2xy(x+y)+(xy+1)(xy-1)=[(x+y)+(xy+1)][(x+y)+(xy-1)]=(x+y+xy+1)(x+y+xy-1);3。原式=x^2+(y-z)x-(6y^2-17yz+12z^2)=x^2+(y-z)x-(3y-4z)(2y-3z)=[x+(3y-4z)][x-(2y-3z)]=(x+3y-4z)(x-2y+3z)。。
热心网友
原题应为这样吧:1。x^2-(m^2+n^2)x+mn(n^2-m^2);2。(x+y)(x+y+2xy)+(xy+1)(xy-1);3。x^2-6y^2-12z^2+xy-xz+17yz。现解答如下:1。原式=x^2-(m^2+n^2)x-mn(m+n)(m-n)=x^2-(m^2+n^2)x+[-m(m+n)][n(m-n)]=[x-m(m+n)][x+n(m-n)]=(x-m^2-mn)(x+mn-n^2);2。原式=(x+y)^2+2xy(x+y)+(xy+1)(xy-1)=[(x+y)+(xy+1)][(x+y)+(xy-1)]=(x+y+xy+1)(x+y+xy-1);3。原式=x^2+(y-z)x-(6y^2-17yz+12z^2)=x^2+(y-z)x-(3y-4z)(2y-3z)=[x+(3y-4z)][x-(2y-3z)]=(x+3y-4z)(x-2y+3z)。。
热心网友
题目好像不对把