求y=(x-1)^2/(x+1)^2 (x>=1 ) 的值域 .谢谢~
y=(x-1)^2/(x+1)^2 (x=1)---√y=(x-1)/(x+1)=1-2/(x+1) (x=1)x=1---0-1=0=0=0=0=热心网友a
a
