已知x 1/x=a 1/a的两个跟分别为a、1/a，那么x 1/(x-1)=a 1/(a-1)的根是多少已知x+1/x=a+1/a的两个跟分别为a、1/a，那么x+1/(x-1)=a+1/(a-1)的根是多少（要有过程）谢谢
热心网友
x+1/(x-1)=a+1/(a-1)(x-1)+1/(x-1)=(a-1)+1/(a-1)令x-1=t ＝t+1/t=(a-1)+1/(a-1)已知x+1/x=a+1/a的两个跟分别为a、1/a所以t=a-1,或t=1/(a-1)把x-1=t 代入 解得，x=a,x=a/(a-1)所以两个根是a，a/(a-1)
热心网友
x+1/x=a+1/a的两个跟分别为a、1/ax-1+1/(x-1)=a-1+1/(a-1)则(x-1)=a=1或1/a-1∴x=a+1或x=a/a-1