乙烷和丙烷的混合气体,完全燃烧后先将产物通过浓H2SO4,浓H2SO4增重2.04g,然后再通过足量的Na2O2,Na2O2增重2.24g.混合气体中乙烷和丙烷的体积比为( )A.1:1 B.2:3 C.3:2 D.3:5要过程的.标况下,11.2L乙烷和丁烷的混合气体完全燃烧时需要氧气47.6L,则原混合气体中乙烷的体积分数为( )A.25% B.50% C.75% D.80%写过程!
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数学化学 都带学字 一样地
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这是高二的化学？我晕！！！！看来是科技是进步的不过感觉更像个数学题不是化学题
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1。CH4, C2H62CO2+2Na2O2=Na2CO3+O2 88`````````````````32````````````````````88-32=56g/mol(每2molCO2通过Na2O2时，Na2O2的增重量） m(CO2)```````````````````````````````````2。24 m(CO2)=88*2。24/56=11*2。24/7=11*0。32=3。52g,```````n(CO2)=3。52/44=0。08mol m(H2O)=2。04g`````````````````````````````````````n(H2O)=2。04/18=0。34/3mol乙烷和丙烷的体积比为:X:Y(X+2Y)/(4X+6Y)=0。08:0。68/3````````````````X:Y=???2。C2H6, C4H10设原混合气体中乙烷的体积分数为:x2C2H6`````+````7O2```=```4CO2```+```6H2O,11。2x``````````11。2x*7/22C4H10````+````13O2``=```8CO2```+```10H2O11。2(1-x)``````11。2(1-x)*13/211。2x*7/2 + 11。2(1-x)*13/2 = 47。6Lx=???。