1∮ x^2/1+e^x dx -1

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原式=∮(1,0)x^2/1+e^x dx+∮(0,-1)x^2/1+e^x dx求第二部分时令x=-u ,可得 ∮(0,-1)x^2/1+e^x dx=∮(1,0)e^x*x^2/1+e^x dx所以原式=∮(1,0)x^2dx=1/3