如果(1/a)+(1/b)+(1/c)=311/1011,求a+b+c=?.
热心网友
1/a + 1/b + 1/c =[(a+b+c)2 - (a2 + b2 + C2)] / 2abc =(a+b+c)/(abc) =311/1011 所以a+b+c=311
如果(1/a)+(1/b)+(1/c)=311/1011,求a+b+c=?.
1/a + 1/b + 1/c =[(a+b+c)2 - (a2 + b2 + C2)] / 2abc =(a+b+c)/(abc) =311/1011 所以a+b+c=311