计算：sin(θ＋75°）＋cos(θ+45°)-√3cosθ＋15°）＝
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答案为0解法如下：sin(θ＋75°）=sin[(θ＋15°）+60°] =sin(θ＋15°）*cos60°+cos(θ＋15°）*sin60° =1/2*sin(θ＋15°）)+√3/2*cos(θ＋15°）sin(θ＋75°）-√3cos(θ＋15°）=1/2*sin(θ＋15°）)-√3/2*cos(θ＋15°） =sin(θ＋15°）*cos60°-cos(θ＋15°）*sin60° =sin(θ-45°）所以，原式=cos(θ+45°)+sin(θ-45°）=0