已知函数f(x)满足f(x y) f(x-y)=2f(x)f(y).且f(0)≠0,若f（2）=2，求f(4)和f(8)的值
热心网友
f(x+0)+f(x-0)=2f(x)f(0) 2f(x)=2f(x)f(0) === f(0)=1f(2+2)+f(2-2)=f(4)+1 = 2f(2)f(2)=8 === f(4)=7f(4+4)+f(4-4)=f(8)+1 = 2f(4)f(4)=98 == f(8)=97
已知函数f(x)满足f(x y) f(x-y)=2f(x)f(y).且f(0)≠0,若f（2）=2，求f(4)和f(8)的值
f(x+0)+f(x-0)=2f(x)f(0) 2f(x)=2f(x)f(0) === f(0)=1f(2+2)+f(2-2)=f(4)+1 = 2f(2)f(2)=8 === f(4)=7f(4+4)+f(4-4)=f(8)+1 = 2f(4)f(4)=98 == f(8)=97