设abc=1 求a/(ab a 1) b/(bc b 1) c/(ac c 1))=?设abc=1 求a/(ab+a+1)+b/(bc+b+1)+c/(ac+c+1))=?求详解
热心网友
a/(ab+a+1)=ac/(1+ac+c)=1/(b+1+bc)b/(bc+b+1)=c/(ac+c+1))=bc/(1+bc+1)a/(ab+a+1)+b/(bc+b+1)+c/(ac+c+1))==1/(b+1+bc)+bc/(1+bc+1)+b/(bc+b+1)=1
设abc=1 求a/(ab a 1) b/(bc b 1) c/(ac c 1))=?设abc=1 求a/(ab+a+1)+b/(bc+b+1)+c/(ac+c+1))=?求详解
a/(ab+a+1)=ac/(1+ac+c)=1/(b+1+bc)b/(bc+b+1)=c/(ac+c+1))=bc/(1+bc+1)a/(ab+a+1)+b/(bc+b+1)+c/(ac+c+1))==1/(b+1+bc)+bc/(1+bc+1)+b/(bc+b+1)=1